WebTo check if a year is a leap year in Python, you can use this function: def is_leap(year): return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0) Here are some example calls to the function: print(is_leap(2000)) # --> True print(is_leap(1900)) # --> False print(is_leap(2016)) # --> True WebFeb 3, 2012 · My code has a end day of 30 but I am having trouble figuring out how to write the code that will discover if its a leap year and set the initial end_date to the correct last …
Program to check if a given year is leap year
WebLeap year in Python The Programming Portal 5.3K subscribers Subscribe 346 Share 24K views 2 years ago INDIA In this video, you will learn how to check if a given year is leap year or... WebJun 18, 2024 · Method 1: Leap Year Program in Python Using If Conditions Copy to clipboard Open code in new window year = int(input("Enter a Year:")) if(year % 4) == 0: if(year % 100) == 0: if(year % 400) == 0: print(" {0} is a leap year". format(year)) else: print(" {0} is not a leap year". format(year)) else: print(" {0} is a leap year". format(year)) … clcf gym
find the leap year in python code example
WebMar 13, 2024 · Python Backend Development with Django(Live) Machine Learning and Data Science. Complete Data Science Program(Live) Mastering Data Analytics; New Courses. Python Backend Development with Django(Live) Android App Development with Kotlin(Live) DevOps Engineering - Planning to Production; School Courses. CBSE Class … WebMay 26, 2015 · You will take an input which will be a year from 1801 to 2400, and output if it is a leap year or not. Your input will have no newlines or trailing spaces: 1954 You will output in any way that you like that clearly tells the user if it is or isn't a leap year (I will accept y or n for yes/no) WebSep 20, 2024 · Check for a Leap Year Using Module In Python, we have calendar module which has a method isleap inside it. The isleap method return True, if the year passed as a parameter is a leap year and False when it is not. Let’s see how it works import calendar year = 2010 if calendar.isleap(year): print("Leap Year") else: print("Not a Leap Year") clc find conveyancer